3x+4y=32
2X+6Y=18 Xएंव yका मान निकाले
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I think that for 2x+ 6y= 18 then for x=3 &y=2
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2(3x+4y=32)=
6x+8y=64
3(2x+6y=18)=
6x+18y=54
subtract second from the first equation then we get
-10y=10
y=-1
3x+4y=32
3x+4(-1)=32
3x=36
X=12
(X,y)=(12,-1)
6x+8y=64
3(2x+6y=18)=
6x+18y=54
subtract second from the first equation then we get
-10y=10
y=-1
3x+4y=32
3x+4(-1)=32
3x=36
X=12
(X,y)=(12,-1)
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