Question

3x+4y=32, 6x-7y=-11 solve by cross multiplication method
please don't send unnecessary answers please help me ​

Answer 1

Answer:

Step-by-step explanation:

3x+4y=32------1, a1=3, b1=4, c1=32

6x-7y=-11-------2, a2=6, b2=-7, c2=-11

Now,

$\frac{x}{b1c2-b2c1}$ = $\frac{y}{c1a2-c2a1}$ = $\frac{1}{a1b2-a2b1}$

$\frac{x}{-44+224} = \frac{1}{-21-24}$

$\frac{x}{180} = \frac{1}{45}$

$x=4$

Also,

$\frac{4}{180}$ = $\frac{y}{192+33}$

$\frac{1}{45}=\frac{y}{225}$

$y=5$

∴ x=4 and y=5 by cross multiplication method

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Answer 2

Answer:

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Step-by-step explanation:

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