3x + 4y = 5 ...............(1), 7x + 5y = 6 ..................(2) so, find the value of x nd y.
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3x + 4y = 5 ---- (1)
7x + 5y = 6 ---- (2)
On solving (1) * 7 & (2) * 3
21x + 28y = 35
21x + 15y = 18
-----------------------
13y = 17
y = 17/13.
Substitute y = 17/13 in (1), we get
3x + 4(17/13) = 5
3x + 68/13 = 5
3x = 5 - 68/13
3x = 65-68/13
3x = -3/13
x = -1/13.
Hope this helps!
7x + 5y = 6 ---- (2)
On solving (1) * 7 & (2) * 3
21x + 28y = 35
21x + 15y = 18
-----------------------
13y = 17
y = 17/13.
Substitute y = 17/13 in (1), we get
3x + 4(17/13) = 5
3x + 68/13 = 5
3x = 5 - 68/13
3x = 65-68/13
3x = -3/13
x = -1/13.
Hope this helps!
siddhartharao77:
:-))
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