Question

3x+4y= 5 and 8x-4y=-16 and x, y?

Answer 1

Solution :

Given pair linear equations ,

3x + 4y = 5 -----( 1 )

8x - 4y = -16 ---( 2 )

Add equations ( 1 ) & ( 2 ) , we get

11x = -11

=> x = ( -11 )/11

=> x = -1

put x = -1 in equation ( 1 ), we get

3( -1 ) + 4y = 5

=> -3 + 4y = 5

=> 4y = 5 + 3

=> 4y = 8

=> y = 8/4

=> y = 2

Therefore ,

( x , y ) = ( -1 , 2 )

•••••

Answer 2

let equation 1,
3x+4y=5
and equation 2,
8x-4y=-16

in equation 1,
3x=5-4y
x=5-4y/3

in equation 2 putting the value of Equation 1,
8(5-4y/3)-4y=-16
y=2

now x=5-4y/3
x=5-4*2/3
x=-1
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