Question

3x-5y=11 , 4x+5y=3 solve by comparison method​

Answer 1

Answer:

$3x - 5y = 11 - - - - (1)\\ 4x + 5y = 3 - - - - (2) \\ by \: \: using \: \: elimination \: \: method \: \\multiply \: \: (1) \: \: by \: \: 4 \\ 4(3x - 5y) = 4(11) \\ 12x - 20y = 44 - - - - (3) \\ multiply \: \: (2) \: \: by \: \: 3 \\ 3(4x + 5y) = 3(3) \\ 12x + 15y = 9 - - - - (4) \\ subtract \: \: (3) \: and \: \: (4) \\ 12x - 20y = 44 \\ 12x + 15y = 9 \\ - 35y = 35 \\ y = \frac{ 35}{ - 35} \\y = - 1 \\ put \: \: value \: \: of \: \: y \: \: in \: (1) \\ 3x - 5( - 1) = 11 \\ 3x + 5 = 11 \\ 3x = 11 - 5 \\ 3x = 6 \\ x = \frac{6}{3} \\ x = 2$

I hope it will help you

Answer 2

Step-by-step explanation:

3x−5y=11−−−−(1)

4x+5y=3−−−−(2)

byusingeliminationmethod

multiply(1)by4

4(3x−5y)=4(11)

12x−20y=44−−−−(3)

multiply(2)by3

3(4x+5y)=3(3)

12x+15y=9−−−−(4)

subtract(3)and(4)

12x−20y=44

12x+15y=9

−35y=35

y=

−35

35

y=−1

putvalueofyin(1)

3x−5(−1)=11

3x+5=11

3x=11−5

3x=6

x=

3

6

x=2