(3x - 5y) ^ 3 - (5x - 2y) ^ 3 + (2x + 3y) ^ 3
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Step-by-step explanation:
3(3x−5y)(5x−2y)(2x+3y)
let a=3x−5y, $$b = 2y - 5x andc = 2x + 3y$$
∴a+b+c=0
Hence, a3+b3+c3=3abc
So, (3x−5y)3−(5x−2y)3+(2x+3y)3
=3(3x−5y)(2y−5x)(2x+3y)
=−3(3x−5y)(5x−2y)(2x+3y)
Answered by
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Answer:
3 ( 3×-5y ) ( 5×-2y) ( 2 ×+3y)
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