Question

3x-5y=4,9x-2y=7 pratistapan vidhi by solve

Answer 1

Answer:

$\Large\boxed{Y=-\frac{5}{13},\quad X=\frac{9}{13}  }$

Step-by-step explanation:

Given:

3x-5y=4, 9x-2y=7 (solve with substitution method.)

$\Large\boxed{\textnormal{SUBSTITUTION METHOD}}$

To solve this problem, only had to do is by using with substitution method.

Solutions:

First, isolate by the x on one side of the equation.

$\displaystyle 3x-5y=4$

Add 5y from both sides.

$\displaystyle 3x-5y+5y=4+5y$

Solve.

$\displaystyle 3x=4+5y$

Divide by 3 from both sides.

$\displaystyle \frac{3x}{3}=\frac{4}{3}+\frac{5y}{3}$

Solve.

$\displaystyle x=\frac{4+5y}{3}$

Solve with x=4+5y/3.

$\displaystyle \begin{bmatrix}9*\frac{4+5y}{3}-2y=7\end{bmatrix}$

Substitute (solve/simplify) by the y=-5/13.

$\displaystyle \frac{4+5(-\frac{5}{13})}{3}$

$\displaystyle \frac{4+5(-\frac{5}{13})}{3}=\frac{9}{13}$

$\Large\boxed{X=\frac{9}{13}, \quad Y=-\frac{5}{13}  }$

As a result, the final answer is y=-5/13 and x=9/13.

Answer 2

$\large{\mathfrak{\underline{\underline{Answer :-}}}}$

x = 9/13 and y = -5/13

${\mathfrak{\underline{\underline{Step-By-Step-Explanation:-}}}}$

Given :-

3x - 5y = 4 ..........[1]

9x - 2y = 7 ..........[2]

$\large{\sf{\star{\boxed{\boxed{By \:substitution \: method}}}}}$

From equation 1

3x - 5y = 4

3x = 4 + 5y

x = 4 + 5y/3 .........[3]

_________[Put values in equation 2]

⇒9(4 + 5y/3) - 2y = 7

⇒3(4 + 5y) - 2y = 7

⇒12 + 15y - 2y = 7

⇒13y = 7 - 12

⇒13y = -5

⇒y = -5/13

$\huge{\boxed{y \: = \: \frac{-5}{13}}}$

________[Put value of y in equation 1]

⇒ 3x -5 (-5/13) = 4

⇒ 3x + 25/13 = 4

[Taking LCM]

⇒ (39x + 25)/13 = 4

⇒ 39x + 25 = 52

⇒ 39x = 52 - 25

⇒39x = 27

⇒x = 27/39

⇒x = 9/13

$\huge{\boxed{x \: = \: \frac{9}{13}}}$