Question

3x - 5y=7 and 9X -15y=3T samikaran dwara asankhya samadhan hele t ra Mana kete​

Answer 1

★ Question ★

The equations 3x - 5y = 7 and 9x - 15y = 21

The equations 3x - 5y = 7 and 9x - 15y = 21have:

a. a unique solution

a. a unique solutionb. no solution

c. infinitely many solutions

many solutionsd. None of the above

★ Answer ★

$\bold{\large {\frac {a_1}{a_2} = \frac {3}{9} = \frac {1}{3}}}$

$\bold{\large{\frac {b_1}{b_2} = \frac {-5}{-15} = \frac {1}{3}}}$

$\bold{\large{\frac {c_1}{c_2} = \frac {7}{21} = \frac {1}{3}}}$

$\bold{\large{\frac {a_1}{a_2} ≠ \frac {b_1}{b_2}}}$

$\bold {\therefore {The \; equations\; have\; a \: unique\; solution}}$

Hence, option (a) is correct.

hope it helps dear...

Answer 2

★ Question ★

The equations 3x - 5y = 7 and 9x - 15y = 21

The equations 3x - 5y = 7 and 9x - 15y = 21have:

a. a unique solution

a. a unique solutionb. no solution

c. infinitely many solutions

many solutionsd. None of the above

★ Answer ★

\bold{\large {\frac {a_1}{a_2} = \frac {3}{9} = \frac {1}{3}}}

a

2

a

1

=

9

3

=

3

1

\bold{\large{\frac {b_1}{b_2} = \frac {-5}{-15} = \frac {1}{3}}}

b

2

b

1

=

−15

−5

=

3

1

\bold{\large{\frac {c_1}{c_2} = \frac {7}{21} = \frac {1}{3}}}

c

2

c

1

=

21

7

=

3

1

\bold{\large{\frac {a_1}{a_2} ≠ \frac {b_1}{b_2}}}

a

2

a

1



=

b

2

b

1

\bold {\therefore {The \; equations\; have\; a \: unique\; solution}}∴Theequationshaveauniquesolution

Hence, option (a) is correct.

hope it helps dear...