Question

3x-6/4+3-5y-4/2=5y/2 x-y/4+x/8-7x-5y/3=y-2x

Answer 1

Step-by-step explanation:

Given 3x-6/4+3-5y-4/2=5y/2 x-y/4+x/8-7x-5y/3=y-2x

• So the two equations are  
•     3x – 3/2 + 3 – 5y – 4/2 – 5y/2 = 0
•       x – y/4 + x/8 – 7x – 5y/3 – y + 2x = 0
• we need to solve the above equations
•  so we have
•        3x – 5y – 5y/2 – 3/2 + 1 = 0
•       6x – 10y – 5y – 3 + 2 / 2 = 0
•          6x – 15y – 1 = 0 ----------------1
•  Now -y/4 + x/8 – 4x – 5y/3 – y = 0
•    Or – 12y + 6x – 192x – 80y – 48y = 0
•     Or – 182 x – 140 y = 0
•    Or x = - 70/41 y
• Substituting the value of x in equation 1 we get
• 6 (- 70 / 41 y) – 15 y = 1
•  So – 420 y / 41 – 15 y = 1
•          Or – 1035 y = 41
•         Or y = - 41 / 1035
•  Now x = (- 70 / 41) (– 41 / 1035)
•     Or x = 14 / 207

Reference link will be

https://brainly.in/question/10572489