3x+7/5=4/5x-12
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can contains a mixture of two liquids A and B is the ratio 7 : 5. When 9 litres of mixture are drawn off and the can is filled with B, the ratio of A and B becomes 7 : 9. How many litres of liquid A was contained by the can initially?
[A].10[B].20[C].21[D].25
Answer: Option C
Explanation:
Suppose the can initially contains 7x and 5x of mixtures A and B respectively.
Quantity of A in mixture left =7x -7x 9litres =7x -21 litres.124
Quantity of B in mixture left =5x -5x 9litres =5x -15 litres.124
7x -214=75x -15 + 949
28x - 21=720x + 219
 252x - 189 = 140x + 147
 112x = 336
 x = 3.
So, the can contained 21 litres of A.
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