Question

3x + 7 Resolve (x + 3) (x2 +1) into partial fractions.
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Answer 1

Answer:

Let

x

2

−3x+2

3x+7

=

(x−2)

A

+

(x−1)

B

⇒3x+7=A(x−1)+B(x−2)

On comparing coefficients 3=A+B,7=−A−2B⇒A=13,B=−10

Thus

x

2

−3x+2

3x+7

=

(x−2)

13

−

(x−1)

10