3x square +1+4x
find its zeroes
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Here is u r answer..
The zeroes are - 1 and - 1/3
The zeroes are - 1 and - 1/3
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3x^2+4x+1
=3x^2+3x+x+1
=3x(x+1) +1(x+1)
=(3x+1)(x+1)
=3x+1=0 =x+1=0
=x=-1/3 or =x=-1
=3x^2+3x+x+1
=3x(x+1) +1(x+1)
=(3x+1)(x+1)
=3x+1=0 =x+1=0
=x=-1/3 or =x=-1
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