Question

3x square-14x-5=0 solve quadratic equation by factorization method

Answer 1

Factoring  3x2-14x-5 

The first term is,  3x2  its coefficient is  3 .
The middle term is,  -14x  its coefficient is  -14 .
The last term, "the constant", is  -5 

Step-1 : Multiply the coefficient of the first term by the constant   3 • -5 = -15 

Step-2 : Find two factors of  -15  whose sum equals the coefficient of the middle term, which is   -14 .

     -15   +   1   =   -14   That's it


Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -15  and  1 
                     3x2 - 15x + 1x - 5

Step-4 : Add up the first 2 terms, pulling out like factors :
                    3x • (x-5)
              Add up the last 2 terms, pulling out common factors :
                     1 • (x-5)
Step-5 : Add up the four terms of step 4 :
                    (3x+1)  •  (x-5)
             Which is the desired factorization.
I HOPE IT WILL HELP YOU

Answer 2

Thus so

_______________________________________________________________

. BY FACTORISATION


. 3 X ² - 14 X - 5 = 0

. 3 X ² - 15 X + X - 5 = 0

. 3 X ( X - 5 ) + 1 ( X - 5 ) = 0

. 3 X + 1 ) ( X - 5 ) = 0


. 3 X + 1 = 0

. X = - 1 / 3


. X - 5 = 0

. X = 5


. Hope it helps

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