Question

a hammer weighing of 1kg moving with the speed of 10ms-1 strikes the head of a nail driving it 10cm in to a wall. neglecting the mass of the nail, calulate(i) the acceleration during the impact (ii) the time interval during the impact an (iii) the impluse. give answer with solution in photo.

Answer 1

from the given question answer should be this if this collison os elastic or inelastic the answer may vary depending on the question

Answer 2

(i) The acceleration during the impact is, -500${\frac{m}{s}}^{2}$.

(ii) The time interval during the impact is 0.02 sec.

(iii) The impluse on the Hammer is -10 Ns.

Explanation:

A hammer is hitting the nail with velocity 10 metre per second and the nail is driven inside the wall up to 10 centimetre.

To calculate acceleration time and Impulse of the reaction the following method is utilized.

(i) $v^2 = u^2 + 2as$

0 = ${10 ms^{-1}}^2 + 2 \times a \times \frac{10}{100}$

a = $\frac{-100}{2\times{\frac{1}{10}}}$

= -500${\frac{m}{s}}^{2}$

The acceleration during the impact is, -500${\frac{m}{s}}^{2}$.

(ii) v = u + at

t = $\frac{v-u}{a}$

t = $\frac{0-10}{-500}$

t = 0.02 sec

The time interval during the impact is 0.02 sec.

(iii)$I = F \times \Delta t$

$I = (m \times a) \times 0.02$

$I = (1 \times -500) \times (0.02)$

I = -10 Ns.

The impluse on the Hammer is -10 Ns.

To know more:

A ball is dropped on to a floor from a height of 10 m. It rebounds to a height of 2.5 m . If the ball is in contact with the floor for 00.01 sec. What is the average acceleration during contact.

(A) 1400 m/s^2

(B) 2100 m/s^2

(C) 700 m/s^2

(D) 2800 m/s^2

https://brainly.in/question/216076