√3x - x= 15√3 find the value of x
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Answered by
1
Answer:
Solve the first part
2sin (3x-15)^{o} = \sqrt{3} 2sin(3x−15)
o
=
3
sin (3x-15)^{o} = \sqrt{3}/2 sin(3x−15)
o
=
3
/2
sin (3x-15)^{o} = sin 60^{o} sin(3x−15)
o
=sin60
o
3x - 15 = 603x−15=60
3x = 753x=75
x = 25x=25
Now substitute the value of 'x' in second part
sin^{2} (2x+10)^{o} + tan^2(x+5)^o sin
2
(2x+10)
o
+tan
2
(x+5)
o
sin^2 60 + tan^2 30sin
2
60+tan
2
30
( \sqrt{3}/2)^2 + (1/ \sqrt{3})^2 (
3
/2)
2
+(1/
3
)
2
3/4 + 1/33/4+1/3
= 13/12=13/12
Answered by
1
Answer:
may be it is right...
I hope it helps youuu
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