Question

3X + Y + 1 = 0 , 2X - 3Y + 8 = 0

Solve it by the method of substitution....

Need answer with full method...

No spam...

Answer 1

Hey friends!!

------------------------------------------------------

Here is your answer↑

------------------------------------------------------

Your answer is in the picture↑

------------------------------------------------------

☺☺☺ hope it is helpful for you ✌✌✌.

Answer 2

Given Equation is 3x + y + 1 = 0  ----- (1)

Given Equation is 2x - 3y + 8 = 0 ---- (2)

Equation (1) can be written as:

= > 3x = -y - 1

= > x = -y - 1/(3)  ------ (3)

Substitute (3) in (2), we get

$= \ \textgreater \ 2\frac{- y - 1}{3} - 3y + 8 = 0$

$= \ \textgreater \ 2( \frac{-y - 1}{3} ) - 3y = -8$

$= \ \textgreater \ 2(-y - 1) - 9y = -24$

$= \ \textgreater \ -2y + 2 - 9y = -24$

$= \ \textgreater \ -11y = -22$

= > y = 2.


Substitute y = 2 in (1), we get

= > 3x + y + 1 = 0

= > 3x + 2 + 1 = 0

= > 3x + 3 = 0

= > 3x = -3

= > x = -1



Therefore the values of x = -1 and y = 2.


Hope this helps!