Question

3x+y=10 find 2 solutions​

Answer 1

$\huge {Answer}$

$3x + y = 10 \\ y = 10 - 3x$

$put \: x = 0$

$y = 10 - 3x \\ y = 10 - 3(0) \\ y = 10 - 0 \\ y = 10$

$put \: x = 1$

$y = 10 - 3x \\ y = 10 - 3(1) \\ y = 10 - 3 \\ y = 7$

$so \: the \: two \: solutions \: are$

(0 , 10) (1 , 7)