Math, asked by ruchi2862, 10 months ago

3x+y+2z=3, 2x-3y-z=-3, x+2y+z=4 solve the equation by inversion method​

Answers

Answered by mohamedabraramjad
0

Answer:

The answer is  

x = 2

,

y = 1 2

, z = − 2

. Please see the explanation for the row operations.

Explanation:

Put the row for x + 2y - z = 5 at the top, because the coefficient of x is 1:

|1 2 -1 |5|

Put the row for 3x + 2y + 2z = 3 next:

|1 2 -1 |5|

|3 2 2|3|

Put the row for 2x -4y + z = last:

|1 2 -1 |5|

|3 2 2|3|

|2 -4 1|0|

Multiply row 1 by -3 and add to row 2:

|1 2 -1 |5|

|0 -4 5|-12|

|2 -4 1|0|

Multiply row 1 by -2 and add to row 3:

|1 2 -1 |5|

|0 -4 5|-12|

|0 -8 3|-10|

Multiply row 2 by -2 and add to row 3:

|1 2 -1 |5|

|0 -4 5|-12|

|0 0 -7|14|

Divide row 3 by -7

|1 2 -1 |5|

|0 -4 5|-12|

|0 0 1|-2|

Multiply row 3 by -5 and add to row 2:

|1 2 -1 |5|

|0 -4 0|-2|

|0 0 1|-2|

Divide row 2 by -4:

|1 2 -1 |5|

|0 1 0|1/2|

|0 0 1|-2|

Add row 3 to row 1:

|1 2 0|3|

|0 1 0|1/2|

|0 0 1|-2|

Multiply row 2 by -2 and add to row 1:

|1 0 0|2|

|0 1 0|1/2|

|0 0 1|-2|

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