3x-y=3 and 9x-3y=9 by using substitution method
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3x-y=3 -----(1)
9x-3y=9------(2)
x= 3+y / 3
9 ( 3+y / 3) = 9
27+9y /3 = 9
27 +9y = 9*3
9y = 27-27
9y =0
y=0/9
y=0
(put value of y in 1st equation)
3x-y=3
3x-0=3
3x=3
x=3/3
x = 1
(1,0)
therefore, value of x and y by substitution method is 1 and 0.
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