Math, asked by Anonymous, 10 months ago

3x-y=3 and 9x-3y=9 by using substitution method​

Answers

Answered by Anonymous
11

3x-y=3 -----(1)

9x-3y=9------(2)

x= 3+y / 3

9 ( 3+y / 3) = 9

27+9y /3 = 9

27 +9y = 9*3

9y = 27-27

9y =0

y=0/9

y=0

(put value of y in 1st equation)

3x-y=3

3x-0=3

3x=3

x=3/3

x = 1

(1,0)

therefore, value of x and y by substitution method is 1 and 0.

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Answered by VIGYAS
2

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