Question

3x+y=30 2y+5z=48 5x-4z=11

Answer 1

3x+y=30. .....eq.1
2y+5z=48. .....eq.2
5x-4z=11. .....eq.3



3x+y=30
Y=3(10-x). .....eq.4

2y+5z=48
Y=(48-5z)/2. .....eq.5


Now from eq.4 and eq.5,we get
3(10-x)=(48-5z)/2
30-3x=(48-5z)/2
60-6x=48-5z
6x-5z=60-48
6x-5z=12. ........eq.6


Now subtracting equation 6 from 3 we get
We get
6x-5z=12
5x-4z=11


30x-25z=60
30x-24z=66

Z=6
X=7
Y=9





Hope it helps...!