Question

3x+y=30 & 2x+5y=33 by substitution method

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Answer 1

Answer:

Step-by-step explanation:

In(ii) substitute the value of y From(i)

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Answer 2

Solution :

$\bf{\red{\underline{\bf{Given\::}}}}$

3x + y = 30

2x + 5y = 33

$\bf{\red{\underline{\bf{To\:find\::}}}}$

The value of x and y.

$\bf{\red{\underline{\bf{Explanation\::}}}}$

We have;

$\bullet\sf{3x+y=30........................(1)}\\\bullet\sf{2x+5y=33......................(2)}}$

$\underline{\underline{\bf{Using\:Substitution\:Method\::}}}}}$

From equation (1),we get;

$\longrightarrow\sf{3x+y=30}\\\\\longrightarrow\sf{3x=30-y}\\\\\longrightarrow\sf{x=\dfrac{30-y}{3} .........................(2)}$

Putting the value of x in equation (2),we get;

$\longrightarrow\sf{2\bigg(\dfrac{30-y}{3}\bigg) +5y=33}\\\\\\\longrightarrow\sf{\dfrac{60-2y}{3} +5y=33}\\\\\\\longrightarrow\sf{60-2y+15y=99}\\\\\\\longrightarrow\sf{60+13y=99}\\\\\\\longrightarrow\sf{13y=99-60}\\\\\\\longrightarrow\sf{13y=39}\\\\\\\longrightarrow\sf{y=\cancel{\dfrac{39}{13} }}\\\\\\\longrightarrow\sf{\pink{y=3}}$

Putting the value of y in equation (3),we get;

$\longrightarrow\sf{x=\dfrac{30-3}{3} }\\\\\\\longrightarrow\sf{x=\cancel{\dfrac{27}{3} }}\\\\\\\longrightarrow\sf{\pink{x=9}}$

Thus;

The value of x is 9 and y is 3 .