Question

3x-y=5, 4x-3y=-1 Hence find p, if y=px-3​

Answer 1

GIVEN :

The equations are 3x-y=5, 4x-3y=-1. Hence find p, if y=px-3​

TO FIND :

The value of p in the given equation y=px-3​

SOLUTION :

Given equations are 3x-y=5, 4x-3y=-1

To  find p, if y=px-3​ :

Let the equations

$3x-y=5\hfill (1)$ and

$4x-3y=-1\hfill (2)$

Now put y=px-3 in equations (1) and (2)

(1) ⇒ 3x-(px-3)=5

3x-px+3=5

$3x-px=2\hfill(3)$

(2) ⇒ 4x-3(px-3)=-1

4x-3px+9=-1

$4x-3px=-10\hfill (4)$

Now multiply the equation (3) into 3 we get

$9x-3px=6\hfill (5)$

Subtracting the equations (4) and (5)

 4x-3px=-10

 9x-3px=6

(-)_(+)__(-)________

 -5x=-16

5x=16

∴ $x=\frac{16}{5}$

Substitute the value $x=\frac{16}{5}$ in equation (1)

$3(\frac{16}{5})-y=5$

$-y=\frac{-48}{5}+5$

$-y=\frac{-48+25}{5}$

$-y=\frac{-23}{5}$

∴ $y=\frac{23}{5}$

Substitute the values  $x=\frac{16}{5}$and $y=\frac{23}{5}$ in equation y=px-3 we get

$\frac{23}{5}=p(\frac{16}{5})-3$

$\frac{23}{5}+3=p(\frac{16}{5})$

$\frac{23+15}{5}=p(\frac{16}{5})$

$\frac{38}{5}=p(\frac{16}{5})$

38=16p

Rewritting as 16p=38

$p=\frac{38}{16}$

∴ $p=\frac{19}{8}$

∴  the value of p is $\frac{19}{8}$ if y=px-3.

Answer 2

Answer:

GIVEN :

The equations are 3x-y=5, 4x-3y=-1. Hence find p, if y=px-3​

TO FIND :

The value of p in the given equation y=px-3​

SOLUTION :

Given equations are 3x-y=5, 4x-3y=-1

To  find p, if y=px-3​ :

Let the equations

and

Now put y=px-3 in equations (1) and (2)

(1) ⇒ 3x-(px-3)=5

3x-px+3=5

(2) ⇒ 4x-3(px-3)=-1

4x-3px+9=-1

Now multiply the equation (3) into 3 we get

Subtracting the equations (4) and (5)

4x-3px=-10

9x-3px=6

(-)_(+)__(-)________

-5x=-16

5x=16

∴  

Substitute the value  in equation (1)

∴  

Substitute the values  and  in equation y=px-3 we get

38=16p

Rewritting as 16p=38

∴  

∴  the value of p is  if y=px-3.

Step-by-step explanation: