Question

3x-y+8=0and 6x-ky=+10

Answer 1

what to do ??? with these equation

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For what value of k, do the equations 3x - y + 8 = 0 and 6x - ky = -16 represent coincident lines?
Asked by Aparna 09/11/2016 Last Modified 07 Jan

CBSE/Class 10/Mathematics Tuition/Class IX-X Tuition Linear Equations


15 Answers


Vimala Ramamurthy

Maths Teacher

19/11/2016
The value of k should be equal to 2, and thus the equations, 3x - y + 8 = 0 and 6x - ky = -16 represent coincident lines
0 Comments

Mamata Mund

Maths Tutor

18/11/2016
a1=3 , b1=-1, c1=8 and a2=6 , b2=-k , c2=16 a1/a2= 3/6=1/2 b1/b2=-1/-k= 1/k c1/c2 = 8/16 =1/2 if a1/a2=b1/b2=c1/c2 then two lines will be coincident 1/2=1/k=1/2 => 1/k=1/2 => k=2
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Umesh Gurnani

Math Magician

18/11/2016
3/6 = (-1)/(-K) = (-8)/(-16)...So k = 2 in this case.
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Abhishek Singh

I have 3 years of experience in this field

18/11/2016
Coincident line should have same slope. So we get the equation 3/(-1) = 6/(-k). solving above equation we get k = 2;
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Shaik Subhani

18/11/2016
In order for two or more straight lines to be coincident, all the coefficients in a straight line must be a multiple of the corresponding coefficients in the other straight line. We have 6x-ky=-16 and this can be written as 6x-ky+16=0 Now 6x-ky+16=0 == A(3x-y+8=0) Equating the coefficients on both... read more
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Sarvajeet Kumar

An Experienced Trainer

19/11/2016
2
0 Comments

Kumar Pn

M.Tech (IIT-Delhi)

21/11/2016
k=2
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Saurabh Shukla

Student

04/12/2016
For two lines to be coincident, the condition is that their ratios of coefficients should be 1. This satisfies only when k=2.
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Kamal Kumar

Be a Educate Person

19/11/2016
if lines are coincident then a1/a2=b1/b2=c1/c2 3/6=-1/-k=8/16 i.e 1/2...therefore k=2
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Sridharla Ramesh

iam tutior i will teach all subjects

18/11/2016
2