Question

√3x2+10x-8√3=0
in words..under root three x square plus ten x minus eight under root three is equal to zero..
find the roots by quadratic formula​

Answer 1

two roots are-

x=-4√3, 2√3/3

Explanation

√3x²+10x-8√3=0

Splitting the middle term, we get

=> √3x²+12x-2x-8√3=0

Rewriting the terms , we get

=> √3x²+(√3x)(4√3)-2x-2×(4√3)=0

=> √3x(x+4√3)-2(x+4√3)=0

=> (x+4√3)(√3x-2)=0

=> x+4√3=0 Or √3x-2 =0

so,

x= -4√3.

or, x= 2/√3 = (2×√3)/(√3×√3) = 2√3 / 3