Question

3x2+2x_1 by splitting the middle term​

Answer 1

$question = 3 {x}^{2} + 2x - 1. \\ \\ solution \\ \\ = 3 {x}^{2} + (3 - 1)x - 1 \\ \\ = 3 {x}^{2} + 3x - x - 1 \\ \\ = 3x(x + 1) - 1(x + 1) \\ \\ = (3x - 1)(x + 1) \: \: is \: the \: answer... \\ hope \: it \: help \: you$

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Answer 2

Answer

(3x−1)(x+1) is the factorised form of the

expression.

Explanation:

3x2+2x−1=0

We can Split the Middle Term of this expression to factorise it.

In this technique, if we have to factorise an expression like

, we need to think of 2 numbers such that:N1⋅N2=a⋅c=3⋅−1=−3

AND

N1+N2=b=2

After trying out a few numbers we get N1=−1

and

N2=3 3⋅ −1=−3 , and 3+(−1)=2 3x2+2x−1=3x2+3x−1x−1 =3x(x+1)−1(x+1) =(3x−1)(x+1) (3x−1)(x+1) is the factorised form of the expression.