Question

3x² - 4√3x + 4=0
find the nature of roots of following quadratic equation


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Answer 1

Answer:

For a quadratic equation ax² + bx + c =0, the term b² - 4ac is called discriminant (D) of the quadratic equation because it  determines  whether the quadratic equation has real roots or not ( nature of roots).

D=  b² - 4ac

So a quadratic equation ax² + bx + c =0, has

i) Two distinct real roots, if b² - 4ac >0 , then x= -b/2a + √D/2a  &x= -b/2a - √D/2a

ii) Two equal real roots, if b² - 4ac = 0 , then x= -b/2a or -b/2a

iii) No real roots, if b² - 4ac <0

SOLUTION:

Given: 3x² – 4√3x + 4 = 0

On Comparing it with ax² + bx + c = 0, we get

a = 3, b = -4√3 and c = 4

Discriminant(D) = b² – 4ac

D= (-4√3)² – 4(3)(4)

D= 16 × 3 - 48

48 – 48 = 0

As , b² – 4ac = 0,

Hence,the given quadratic equation has  real and equal roots.

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Answer 2

Answer:

Hope so it is helping you

Step-by-step explanation:

3x^2 -4√3x +4 =0

D= b^2-4ac

(-4√3)^2-4×3×4

On solving

We get

48-48=0

D=0 means roots are real and equal in nature