Math, asked by adityakumar14, 1 year ago

3x²+5x-2=0
3x { }^{2}  + 5x - 2 = 0


Khanz: 3x² + 5x -2, 3x² -(6-1)x -2, 3x² - 6x + x -2, 3x(x-2)+1(x-2), (3x+1)(x-2)
karthik413477: its wrong
Khanz: why
karthik413477: in 2nd step you wrote -5x instead of +5x watch properly

Answers

Answered by karthik413477
5
3x^2+6x-x-2=0
(3x-1)(x+2)=0
x=-2,x=1/3
Answered by Anonymous
11
3x²+5x-2=0
3x²+(6-1)x-2=0
3x²+6x-x-2=0
3x(x+2)-1(x+2)=0
(x+2)(3x-1)=0
x=-2 or x=1/3
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