Question

a Cheetah is starts from rest and accelerate at 2 metre per second square from 10 second calculate the final velocity and the distance travelled

Answer 1

hey !! your answer is here --

given , acceleration a = 2m/s^2 , t = 10 sec
since , cheetah is started from rest
so, initial velocity u = 0
now , we know that -
v = u + at
=> v = 0 + 2 × 10
=> (v = 20 m/s )
now , we also know that-

$v {}^{2} = u {}^{2} + 2as$
=> $20 {}^{2} = 0 {}^{2} + 2 \times 2 \times s$

=> 400 = 4s

=> s = 400/4

=> s = 100 m

hence , finally velocity v = 20m/s^2
and. distance s = 100m

hope you like & understand
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Answer 2

²²initial velocity of cheetah=u=0

acceleration =2 m/s

total time =10 s

applying the property

v=u+at

   =>0 +2*10

   =>20 m/s

the final velocity=20 m/s

again v² +u² =2as

20² +0²=2×2×s

400=4s

s=100 m

here s= distance

v=final velocity

u initial velocity

a= acceleration

hope this helps u

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