(3x²+5x-7) (x-1) - (x²2x+3)(x +4)
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Answer:
(3x²+5x-7)(x-1)-(x²-2x+3)(x+4)
=(3x³+5x²-7x-3x²-5x+7)-(x³-2x²+3x+4x²-8x+12)
=(3x³+2x²-12x+7)-(x³+2x²-5x+12)
=3x³+2x²-12x+7 -x³-2x²+5x-12
=2x³-7x-5
hope it helps you...
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