3x2-8x+3 find the root by completing the square
Answers
Answered by
4
Hi Mate!!!
3x² - 8x + 3 = 0
Step 1 :- Dividing both sides by 3
x² - ( 8 / 3 )x + 1 = 0
x² - 2 ( x ) ( 4 / 3 ) + 16 / 9 - 16 / 9 +1 =0
( x - 4 / 3 )² = 7 / 9
x = ( √7 + 4 ) / 3 or x = ( -√7 + 4 ) / 3
Have a nice time..
3x² - 8x + 3 = 0
Step 1 :- Dividing both sides by 3
x² - ( 8 / 3 )x + 1 = 0
x² - 2 ( x ) ( 4 / 3 ) + 16 / 9 - 16 / 9 +1 =0
( x - 4 / 3 )² = 7 / 9
x = ( √7 + 4 ) / 3 or x = ( -√7 + 4 ) / 3
Have a nice time..
Similar questions