Question

3x²+x-2 I need answer
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Answer 1

Answer:

3x^2+x-2

3x^2+3x-2x-2

3x[x+2]-2[x+2]

[3x-2] [x+2]

Answer 2

Answer:

3x^2 + x - 2

3x^2 +3x-2x-2 = 0

3x(x - 1) - 2(x - 1) =0

(x-1) (3x-2) =0

x= 1 or x=2/3

1 will get rejected if you put in equation as it does not satisfy it... therefore x =2/3

I hope that helps