Question

3x²y - 4 and 6xy² + 8 Add them.

Answer 1

3x2y + 6xy2 +4
3x2y + 6xy2 +4
3x2y + 6xy2 +4
3x2y + 6xy2 +4
3x2y + 6xy2 +4
3x2y + 6xy2 +4

Answer 2

Answer:

3xy (x +2y) + 4

Step-by-step explanation:

As per the question,

We have been provided the two equation,

The first equation is 3x²y - 4 . Say this equation be = E₁

The other equation is 6xy² + 8. Say this equation be = E₂

Now,

On adding both, we get

E₁ + E₂

= (3x²y - 4) + (6xy² + 8)

= 3x²y + 6xy² + 4

Now take common 3xy from 3x²y + 6xy², we get

= 3xy (x +2y) + 4

Hence, the required answer is 3xy (x +2y) + 4.