Question

3xsquare-110x+600
find the factorization
​

Answer 1

Answer:

Step by Step Solution

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Step by step solution :

STEP

1

:

Equation at the end of step 1

(3x2 - 110x) + 600 = 0

STEP

2

:

Trying to factor by splitting the middle term

2.1 Factoring 3x2-110x+600

The first term is, 3x2 its coefficient is 3 .

The middle term is, -110x its coefficient is -110 .

The last term, "the constant", is +600

Step-1 : Multiply the coefficient of the first term by the constant 3 • 600 = 1800

Step-2 : Find two factors of 1800 whose sum equals the coefficient of the middle term, which is -110 .

-1800 + -1 = -1801

-900 + -2 = -902

-600 + -3 = -603

-450 + -4 = -454

-360 + -5 = -365

-300 + -6 = -306

-225 + -8 = -233

-200 + -9 = -209

-180 + -10 = -190

-150 + -12 = -162

-120 + -15 = -135

-100 + -18 = -118

-90 + -20 = -110 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -90 and -20

3x2 - 90x - 20x - 600

Step-4 : Add up the first 2 terms, pulling out like factors :

3x • (x-30)

Add up the last 2 terms, pulling out common factors :

20 • (x-30)

Step-5 : Add up the four terms of step 4 :

(3x-20) • (x-30)

Which is the desired fac

Answer 2

Step-by-step explanation:

3x² - 110x + 600

• Using Middle Term Factorization
• 3 × 600
• 3 * 3 * 2 * 10 * 10
• 90 * 20

3x² - 90x - 20x + 600

3x(x - 30) - 20(x - 30)

(x - 30) (3x - 20)

x = 30 or 20/3