3xsquare+11x+6=0please
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Answered by
3
3x²+11x+6=0
3x²+9x+2x+6=0
3x(x+3)+2(x+3)=0
(x+3)(3x+2)=0
x=-3 and x=-2/3
3x²+9x+2x+6=0
3x(x+3)+2(x+3)=0
(x+3)(3x+2)=0
x=-3 and x=-2/3
Answered by
1
heya maTe here is the Answer ●_●
3x2+11x+6=0●_●
transpose 6 to r. h.s ●_●
3x2+11x=-6●_●
take x as common... ●_●
we can write as ...●_●
x(3x+11)=6 ●_●
so we can evaluate the value of x as 6 or
-5/3...●_●
if my answer is correct pls mark my answer as brainliest ●_●
3x2+11x+6=0●_●
transpose 6 to r. h.s ●_●
3x2+11x=-6●_●
take x as common... ●_●
we can write as ...●_●
x(3x+11)=6 ●_●
so we can evaluate the value of x as 6 or
-5/3...●_●
if my answer is correct pls mark my answer as brainliest ●_●
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