Question

√3xsquare +2 √3x+ √3=0 determine nature of root of the given quadratic equations

Answer 1

Answer:

Roots are equal

Step-by-step explanation:

to find nature of roots we have to take b^2-4ac(discriminant)

if b^2-4ac=0:roots are equal and real

if b^2-4ac>0:roots are distinct and real

if b^2-4ac<0:roots are imaginary

here b^2-4ac gives

(2$\sqrt{3}$)^2-4$\sqrt{3}$*$\sqrt{3$

12-12=0

so roots are real and equal

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