Question

3xsquare + 5 x -2 ≤ 0​

Answer 1

Step-by-step explanation:

We have,

$3 {x}^{2} + 5x - 2 \leqslant 0$

$\implies 3 {x}^{2} + 6x - x - 2 \leqslant 0$

$\implies 3x(x + 2) - 1(x + 2) \leqslant 0$

$\implies (3x - 1)(x + 2) \leqslant 0$

$\implies 3 \bigg(x - \frac{1}{3} \bigg)(x + 2) \leqslant 0$

$\implies \bigg(x - \frac{1}{3} \bigg)(x + 2) \leqslant 0$

$\implies x \in \bigg[ - 2 , \frac{1}{3} \bigg ]$