3xsquare+x-4 find the zeroes, sum, and product
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hey mate
given here equation
3x^2+x-4=0
let ,
zeroes of given equation
p and q
then,
sun of zeros = -(coffi. of x)/(coffee.of x^2)
p+q= -(1)/3
= -1/3.
and ,
product of zeros =(constants part )/(coffee.of x^2)
p.q= -4/3.
I hopes its helps u.
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