Math, asked by kb5454604, 5 months ago

3xy-y²+6xz-2yz evaluate​

Answers

Answered by rameshchandrasoni149
0

Answer:

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Step-by-step explanation:

Do the grouping 3x

2

+xy−6xz−2yz=(3x

2

+xy)+(−6xz−2yz), and factor out x in the first and −2z in the second group.

x(3x+y)−2z(3x+y)

Factor out common term 3x+y by using distributive property.

(3x+y)(x−2z)

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