Question

3y^3+1×3y^2-2y-2+4y^2+5y+7​

Answer 1

Step-by-step explanation:

have,

4y(3y

2

+5y−7)+2(y

3

−4y

2

+5)

⇒12y

3

+20y

2

−28y+2y

3

−8y

2

+10

⇒14y

3

+12y

2

−28y+10

Hence, this is the answer.

Answer 2

$\huge\tt \blue{ \fbox \colorbox{black}{answer}}$

4y(3y

2

+5y−7)+2(y

3

−4y

2

+5)

⇒12y

3

+20y

2

−28y+2y

3

−8y

2

+10

⇒14y

3

+12y

2

−28y+10