Question

3y+3/y×3=27 value of y​

Answer 1

Answer:

3y+3/y=27/3=9

LCM of 1 and y=y

3y^2+3/y=9

3y^2+3=9y

3y^2-9y+3=0

Now factorise it

Answer 2

Answer:

The value of y is

$y = \frac{1}{26}$

Step-by-step explanation:

The given relation is written as

$\frac{3y + 3}{3y} = 27$

Taking the term 3 as common in both numerator and denominator we get

$\frac{3(y + 1)}{3y} = 27 \\ = > 1 + \frac{1}{y} = 27 = > \frac{1}{y} = 27 - 1 = 26 \\ = > y = \frac{1}{26}$

Therefore,the value of y is found to be

$y = \frac{1}{26}$

#SPJ2