Question

3y+5. 3-2y=5\3 solve the following​

Answer 1

Answer:

when we cross multiply it then:-

3(3y+5). = 5(3-2y)

9y+15. = 15-10y

9y+10y. = 15-15

19y. = 0

y. = 0/19

i.e. y=0

Hope this helps you

Answer 2

Answer:

0

Step-by-step explanation:

3y+5/3-2y=5/3

3(3y+5)=5(3-2y

9y+15=15-10y

9y+10y=15-15

19y=0

y=0/19

y=0