Question

(3y-7)3 solve by identities

Answer 1

hey here is your answer
${(3y - 7)}^{3} \\ using \: identity \: {(a - b)}^{3} = \\ = {a}^{3} - {b}^{3} - 3ab(a - b) \\ {(3y - 7)}^{3} = \\ = {(3y)}^{3}- {(7)}^{3} - 3 \times 3y \times 7(3y - 7) \\ = 27 {y}^{3} - 343 - 189 {y}^{2} + 441y$
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