Math, asked by bhumiraajsinghr9791, 11 months ago

3y(y+7)/(y+7)(y2-9)
i want it solve

Answers

Answered by bhubaneswari72
0

Answer:

3y(y+7)/(y+7)(y2-9)

3y^2+21y/2y^2+14y-9y-63

3y^2+21y/2y^2-5y-63

we use formula method

-b+or-√b^2-4ac/2a

-(-5)+or-√(-5)^2-4(2)(-63)/2(2)

5+or-√25+504/4

5+or-√529/4

5+or-23/4

5+23/4 or 5-23/4

28/4 or -18/4

7 or -9/2

we not consider negative

so, y = 7

by substitute y value given equation

3y(y+7)/(y+7)(y2-9)

3(7)^2+21(7)/2(7)^2-5(7)-63

3×49+147/98-35-63

147+147/0

294/0

the value of 3y(y+7)/(y+7)(y2-9)

is "undefined".

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