3y(y+7)/(y+7)(y2-9)
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Answer:
3y(y+7)/(y+7)(y2-9)
3y^2+21y/2y^2+14y-9y-63
3y^2+21y/2y^2-5y-63
we use formula method
-b+or-√b^2-4ac/2a
-(-5)+or-√(-5)^2-4(2)(-63)/2(2)
5+or-√25+504/4
5+or-√529/4
5+or-23/4
5+23/4 or 5-23/4
28/4 or -18/4
7 or -9/2
we not consider negative
so, y = 7
by substitute y value given equation
3y(y+7)/(y+7)(y2-9)
3(7)^2+21(7)/2(7)^2-5(7)-63
3×49+147/98-35-63
147+147/0
294/0
the value of 3y(y+7)/(y+7)(y2-9)
is "undefined".
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