Question

The distance between the point p(1,4)and (4,0) is

Answer 1

Answer:

5units is the distance between the points (1,4) and (4,0).

Step-by-step explanation:

Explanation:

Given, two points (1,4) and (4,0).

As we know that, the distance formula = $\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Step 1:

So, from the question we have,

$x_1 = 1 , y_1 = 4 , x_ 2= 4\ and\ y_2 = 0$.

∴Distance = $\sqrt{(4- 1)^2 + (0-4)^2}$

Distance = $\sqrt{3^2 + 4^2}$ = $\sqrt{9 + 16} = \sqrt{25}$ =  5units.

Final answer:

Hence, the distance between the points is 5 units.

#SPJ3