Question

3y² + 1Oy-8 factorise.​

Answer 1

Answer:

3y² + 1Oy-8

=3y² - 12y +2y-8

=3y(y-4)+2(y-4)

=(y-4)(3y+2)(Ans.)

Step-by-step explanation:

Please mark my answer as brainliest

Answer 2

Answer:

3y² +10y -8.

Step-by-step explanation:

we have to find the LCM of the product of the coefficient of y² and -8 that is, 3 and 8. which is 24. so now, we have to factorize it. 12 times 2 is 24 and 12-2 is 10( which is the value we needed. this method is called median in my country.)

now, you can say that 4 times 6 is also 24. but the values 4 and 6 are both positive. we need one positive and one negative value.

first, if you do it with 12-2,

3y² +12y -2y -8

= 3y( y+4) -2(y+4) { here we took 3y as common between 3y² and 12y. we took common -2 between -2 and -8}

= (y+4) (3y-2) [ans]