Question

3y²+4y-7+y²+y+12

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Answer 1

Answer:

=> 3y²+4y-7+y²+y+12

=> 3y²+y²+4y+y-7+12 [combining like terms]

= 4y²+5y+5

Step-by-step explanation:

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Answer 2

Answer:

4y^2+5y+5

Step-by-step explanation:

STEP

1

:

Equation at the end of step 1

 ((((3y2 +  4y) -  7) +  y2) +  y) +  12

STEP

2

:

Trying to factor by splitting the middle term

2.1     Factoring  4y2+5y+5

The first term is,  4y2  its coefficient is  4 .

The middle term is,  +5y  its coefficient is  5 .

The last term, "the constant", is  +5

Step-1 : Multiply the coefficient of the first term by the constant   4 • 5 = 20

Step-2 : Find two factors of  20  whose sum equals the coefficient of the middle term, which is   5 .

answer - 4y2 + 5y + 5

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