Math, asked by nasimhossain336, 9 months ago

4^1/3×[2^1/3×3^1/2]÷9^1/4​

Answers

Answered by charu47Sa
9

Answer:

2

Step-by-step explanation:

=2^(2×1/3)×[2^1/3 × 3^1/2]/3^(2×1/4)

=(2^2/3×2^1/3×3^1/2)/3^1/2

=2^2/3×2^1/3

=2^(2/3 +1/3)

=2^3/3

=2^1

=2

mark brainliest

Answered by Anonymous
133

\LARGE{\underline{\red{\sf{Required\:answer:}}}}

 {4}^{ \frac{1}{3} }  \times ( {2}^{ \frac{1}{3} }  \times  {3}^{ \frac{1}{2} } ) \div  {9}^{ \frac{1}{4} }  \\  =  { ({2}^{2}) }^{ \frac{1}{3} }  \times  {2}^{ \frac{1}{3} }  \times  {3}^{ \frac{1}{2} }  \div  { ({3}^{2} )}^{ \frac{1}{4} }  \\  =  \frac{ { ({2}^{2}) }^{ \frac{1}{3} }  \times  {2}^{ \frac{1}{3}  } \times  {3}^{ \frac{1}{2} }  }{  { ({3}^{2}) }^{ \frac{1}{2} } }  \\  =  \frac{ {2}^{ \frac{2}{3} } \times  {2}^{ \frac{1}{3} }  \times  {3}^{ \frac{1}{2} }  }{ {3}^{ \frac{1}{2} } }  \\  =   {2}^{ \frac{2}{3}  +  \frac{1}{3}  }  \times  {3}^{ \frac{1}{2}  -  \frac{1}{2} }  \\  =  {2}^{ \frac{2 + 1}{3} }  \times  {3}^{0}  \\  =  {2}^{ \frac{3}{3} }  \times 1 \\  =  {2}^{1}  \times 1 \\  = 2

\LARGE{\underline{\blue{\sf{hope \: it \: helps \: u \: \:}}}}

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