Question

(4^-1+8^-1 ) ×[4/9]^2
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Answer 1

$\huge \bigstar { \underline{ \mathtt{ \red{A}{ \pink{n}{ \color{blue}{s}{ \color{gold}{w}{ \color{aqua}{e}{ \color{lime}{r}}}}}}}}}★$

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$= > ( {4}^{ - 1} + {8}^{ - 1} ) \times {( \frac{4}{9} )}^{2} \\ \\ = > ( \frac{1}{4} + \frac{1}{8} ) \times \frac{16}{81} \\ \\ = > \frac{3}{8} \times \frac{16}{81} \\ \\ = > \frac{2}{27}$

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Hope it's helpful to you

Answer 2

$\huge \bigstar { \underline{ \mathtt{ \red{A}{ \pink{n}{ \color{blue}{s}{ \color{gold}{w}{ \color{aqua}{e}{ \color{lime}{r}}}}}}}}}★$

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$</p><p></p><p>\begin{gathered} = > ( {4}^{ - 1} + {8}^{ - 1} ) \times {( \frac{4}{9} )}^{2} \\ \\ = > ( \frac{1}{4} + \frac{1}{8} ) \times \frac{16}{81} \\ \\ = > \frac{3}{8} \times \frac{16}{81} \\ \\ = > \frac{2}{27} \end{gathered}$

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✏ Hope it's helpful to you ••••