Question

4.15 g of an acid are dissolved in water and volume of solution is made 500 ml by
adding water. 20 ml of N/10 Naoh solution for neutralization
​

Answer 1

Answer:

4.15 g of an acid are dissolved in water and volume of solution is made 500 ml by

adding water. 20 ml of N/10 Naoh solution for neutralization

Explanation:

Answer 2

Concept:

The amount of solute in a solution measured in grams or moles per liter is referred to as normality. The amount of moles of reactive units in a compound is known as normality. It is frequently referred to as the equivalent concentration of a solution and is abbreviated as "N".

Given:

The mass of an acid = 4.15 g

The volume of solution = 500 mL

The volume of sodium hydroxide solution = 20 mL

The normality of sodium hydroxide solution = N/10

Find:

Find the molar mass of the acid used in the neutralization reaction.

Solution:

Applying the normality equation,

            N₁V₁  =  N₂V₂

     (Acid)         (NaOH)

By substituting the given values in the above expression we can get the normality of acid solution.

N₁ * 500 mL = 1/10 * 20 mL

N₁ =  (1/10 N * 20 mL) / 500 mL

N₁ = (20 / 500) N

N₁ = 0.04 N

Hence, the normality of the acid solution is 0.04 N.

The mass of acid in 500 mL solution = 4.15 g

Normality = mass of acid / (equivalent mass * Volume of solution in L)

0.04 N = 4.15 g /(equivalent mass * 500 * 10⁻³ L)

Equivalent mass = 4.15 g / (0.04 g/L * 0.5 L)

Equivalent mass = (4.15 / 0.02) = 207.5

The molar mass of the acid can be calculated as:

Molar mass = Mass of acid in g / Equivalent mass of acid

Molar mass = 4.15 g / 207.5

Molar mass = 0.02 g/mol

Hence, the molar mass of acid is 0.02 g/mol.

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