Math, asked by prashantdhaked2774, 9 months ago

4√2 + 3√32 Simply the following in irrational number

Answers

Answered by bbgdu
0

Answer:

4 \sqrt{2} +  12 \sqrt{2}

16 \sqrt{2}

Step-by-step explanation:

3 \times  \sqrt{32}  \\  3 \times \sqrt{16 \times 2}   \\  3 \times \sqrt{16} \times  \sqrt{2} \\   3 \times 4 \sqrt{2} \\ 12 \sqrt{2}

Answered by gurman0
0

Answer:

4 \sqrt[]{2}  + 3 \sqrt[]{32}  \\ 4 \sqrt[]{2}  + 3 \sqrt[]{2  {}^{5} }  \\ 4  \sqrt{2}  + 3  \times 2 \times 2  \sqrt{2} \\ 4 \sqrt{2}   + 12 \sqrt{2}  \\ 16 \sqrt{2}

Step-by-step explanation:

I think it works

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